The pH of a solution is 2. If its pH is to be | vedclass

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(D) The $pH$ of a solution is defined as $pH = -\log[H^{+}]$,which implies $[H^{+}] = 10^{-pH}$.For the original solution with $pH = 2$,the concentrat

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Decreased hundred times

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(D) The $pH$ of a solution is defined as $pH = -\log[H^{+}]$,which implies $[H^{+}] = 10^{-pH}$.For the original solution with $pH = 2$,the concentration is $[H^{+}]_{1} = 10^{-2} \ M$.For the final solution with $pH = 4$,the concentration is $[H^{+}]_{2} = 10^{-4} \ M$.The ratio of the concentrations is $\frac{[H^{+}]_{1}}{[H^{+}]_{2}} = \frac{10^{-2}}{10^{-4}} = 10^{2} = 100$.Therefore,the $[H^{+}]$ concentration must be decreased by a factor of $100$ to raise the $pH$ from $2$ to $4$.

The $pH$ of a solution is $2$. If its $pH$ is to be raised to $4$,then the $[H^{+}]$ of the original solution has to be

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