The e.m.f. of the following galvanic cells ar | vedclass

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(D) The cell reaction is $Zn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s)$.Using the Nernst equation: $E_{cell} = E^o_{cell} - \frac{0.0591}{2} \l

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$E_2 > E_1 = E_4 > E_3$

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(D) The cell reaction is $Zn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s)$.Using the Nernst equation: $E_{cell} = E^o_{cell} - \frac{0.0591}{2} \log \frac{[Zn^{2+}]}{[Cu^{2+}]}$.For $(i): E_1 = E^o_{cell} - \frac{0.0591}{2} \log \frac{1}{1} = E^o_{cell}$.For $(ii): E_2 = E^o_{cell} - \frac{0.0591}{2} \log \frac{0.1}{1} = E^o_{cell} + 0.02955$.For $(iii): E_3 = E^o_{cell} - \frac{0.0591}{2} \log \frac{1}{0.1} = E^o_{cell} - 0.02955$.For $(iv): E_4 = E^o_{cell} - \frac{0.0591}{2} \log \frac{0.1}{0.1} = E^o_{cell}$.Comparing the values: $E_2 > E_1 = E_4 > E_3$.

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