The $emf$ of the cell reaction is $1.1 \ V$. Calculate the free energy change for the reaction in $kJ$:
$Zn_{(s)} + Cu^{+2}_{(aq)} \longrightarrow Zn^{+2}_{(aq)} + Cu_{(s)}$

  • A
    $-106.3$
  • B
    $-298.3$
  • C
    $+463.8$
  • D
    $-212.3$

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