The N atom which does not contribute to the b | vedclass

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(A) The given compound is purine. In purine,the lone pair of electrons on the $N-9$ atom is involved in the aromatic sextet of the imidazole ring. The

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$N-9$

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(A) The given compound is purine. In purine,the lone pair of electrons on the $N-9$ atom is involved in the aromatic sextet of the imidazole ring. Therefore,this lone pair is not available for protonation,and $N-9$ does not contribute to the basicity of the compound. Other nitrogen atoms $(N-1, N-3, N-7)$ have lone pairs in $sp^2$ hybridized orbitals that are not involved in aromaticity,making them available for protonation.

The $N$ atom which does not contribute to the basicity of the given compound is:

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