The B-H curve for a ferromagnet is shown in t | vedclass

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(B) From the given $B-H$ curve,the coercivity of the ferromagnet is the value of $H$ at which $B=0$. From the graph,this value is $H = 100 	ext{ A/m}

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$1 	ext{ mA}$

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(B) From the given $B-H$ curve,the coercivity of the ferromagnet is the value of $H$ at which $B=0$. From the graph,this value is $H = 100 	ext{ A/m}$.The number of turns per unit length of the solenoid is $n = 1000 	ext{ turns/cm} = 1000 	imes 100 	ext{ turns/m} = 10^5 	ext{ turns/m}$.The magnetic field intensity inside a long solenoid is given by $H = nI$,where $I$ is the current.To demagnetize the ferromagnet,we need to apply a magnetic field intensity equal to the coercivity,so $H = 100 	ext{ A/m}$.Substituting the values into the formula: $100 = 10^5 	imes I$.Solving for $I$: $I = \frac{100}{10^5} = 10^{-3} 	ext{ A} = 1 	ext{ mA}$.

The $B-H$ curve for a ferromagnet is shown in the figure. The ferromagnet is placed inside a long solenoid with $1000 \text{ turns/cm}$. The current that should be passed in the solenoid to demagnetize the ferromagnet completely is

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