The IUPAC name of the given structure is: CH_ | vedclass

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(B) $1$. Identify the principal functional group: The aldehyde group $(-CHO)$ has the highest priority and must be assigned the lowest possible number

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$3-$Methylpent$-4-$enal

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(B) $1$. Identify the principal functional group: The aldehyde group $(-CHO)$ has the highest priority and must be assigned the lowest possible number,so it is carbon $1$.$2$. Select the longest carbon chain containing the principal functional group and the double bond: The chain has $5$ carbons,so the parent alkane is pentane.$3$. Number the chain: Starting from the aldehyde carbon as $C-1$,the double bond starts at $C-4$ and the methyl group is at $C-3$.$4$. Combine the parts: The parent is $pent-4-enal$. With a methyl group at position $3$,the name is $3-methylpent-4-enal$.

The $IUPAC$ name of the given structure is: $CH_2=CH-CH(CH_3)-CH_2-CHO$

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