The IUPAC name of the compound is | vedclass

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(B) To determine the $IUPAC$ name,we follow the lowest locant rule for numbering the benzene ring substituents.$1$. The substituents are $F$ (fluoro),

Vedclass · Accepted Answer

$2-$Bromo$-1-$chloro$-5-$fluoro$-3-$iodobenzene

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(B) To determine the $IUPAC$ name,we follow the lowest locant rule for numbering the benzene ring substituents.$1$. The substituents are $F$ (fluoro),$Cl$ (chloro),$Br$ (bromo),and $I$ (iodo).$2$. Numbering the ring starting from $Cl$ as $1$,$Br$ as $2$,$I$ as $3$,and $F$ as $5$ gives the locant set $(1, 2, 3, 5)$.$3$. According to the alphabetical order of substituents (Bromo,Chloro,Fluoro,Iodo),the name is constructed as $2-$bromo$-1-$chloro$-5-$fluoro$-3-$iodobenzene.$	herefore$ The correct $IUPAC$ name is $2-$bromo$-1-$chloro$-5-$fluoro$-3-$iodobenzene.

Column-$(I)$	Column-$(II)$
$(A)$ $CH_3CH_2X$	$(1)$ $4^{\circ}$ halide
$(B)$ $R'CH_2X$	$(2)$ $3^{\circ}$ halide
$(C)$ $R'R''CHX$	$(3)$ $2^{\circ}$ halide
$(D)$ $R'R''CR'''X$	$(4)$ $1^{\circ}$ halide

Column-$I$ (Structure)	Column-$II$ (Hybridization)
$A$. $CH_3CH_2Cl$	$i$. $sp$
$B$. $CH_2=CHCl$	$ii$. $sp^2$
$C$. $CH_2=CH-CH_2Cl$	$iii$. $sp^3$
$D$. Chlorobenzene	$iv$. $sp^3d$

The $IUPAC$ name of the compound is

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