The E_2 product of the following reaction wil | vedclass

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(A) In an $E_2$ elimination reaction,the leaving group $(-Br)$ and the $\beta$-hydrogen must be in an anti-periplanar conformation.In the given cycloh

Vedclass · Accepted Answer

$3-$methylcyclohexene

Vedclass · Answer

(A) In an $E_2$ elimination reaction,the leaving group $(-Br)$ and the $\beta$-hydrogen must be in an anti-periplanar conformation.In the given cyclohexane derivative,the $-Br$ group is in an axial position.The $\beta$-hydrogen at the $C_3$ position is also in an axial position,which is anti to the $-Br$ group.Therefore,the elimination occurs between $C_1$ and $C_2$ to form $3$-methylcyclohexene as the major product.

The $E_2$ product of the following reaction will be?

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