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Question

(B) $1$. Identify the principal functional group: The $-OH$ group has higher priority than the double bond,so it gets the lowest possible locant,$1$.

Vedclass · Accepted Answer

$5-$Methylcyclopent$-2-$en$-1-$ol

Vedclass · Answer

(B) $1$. Identify the principal functional group: The $-OH$ group has higher priority than the double bond,so it gets the lowest possible locant,$1$. $2$. Number the ring: Start numbering from the carbon attached to the $-OH$ group as $1$. To give the double bond the lowest locant,proceed towards the double bond. $3$. Numbering path: If we number clockwise,the double bond starts at $C-2$. If we number counter-clockwise,the double bond starts at $C-4$. Thus,clockwise is correct. $4$. Assign locants: The $-OH$ is at $C-1$,the double bond starts at $C-2$,and the methyl group is at $C-5$. $5$. Construct the name: The parent chain is cyclopentene. Combining these,we get $5-$methylcyclopent$-2-$en$-1-$ol.

The $IUPAC$ name of the compound is:

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