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(C) Since the temperature is constant,we use Boyle's Law: $P_1 V_1 = P_2 V_2$.Let the initial pressure be $P$ and initial volume be $V$.The pressure i

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increases by $25 \%$

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(C) Since the temperature is constant,we use Boyle's Law: $P_1 V_1 = P_2 V_2$.Let the initial pressure be $P$ and initial volume be $V$.The pressure is decreased by $20 \%$,so the new pressure $P_2 = P - 0.20P = 0.80P$.Substituting into the equation: $P 	imes V = 0.80P 	imes V_2$.Solving for $V_2$: $V_2 = \frac{V}{0.80} = 1.25V$.The change in volume is $\Delta V = V_2 - V = 1.25V - V = 0.25V$.The percentage change in volume is $\frac{\Delta V}{V} 	imes 100 = 0.25 	imes 100 = 25 \%$.Since the result is positive,the volume increases by $25 \%$.

Temperature remaining constant,the pressure of a gas is decreased by $20 \%$. What is the percentage change in volume?

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