Tanks $A$ and $B$ open at the top contain two different liquids up to a certain height. $A$ hole is made in the wall of each tank at a depth $h$ from the surface of the liquid. The area of the hole in $B$ is twice that of the hole in $A$. If the liquid mass flux through each hole is equal,then the ratio of the densities of the liquids,$\rho_A / \rho_B$,is:

$A$ large storage tank,open to the atmosphere at the top and filled with water,develops a small hole in its side at a point $20.0 \ m$ below the water level. If the rate of flow from the hole is $3.08 \times 10^{-5} \ m^3 s^{-1}$,then the diameter of the hole is (Take $g = 10 \ m s^{-2}$): (in $mm$)

$A$ cylinder of height $h$ is filled with water and is kept on a block of height $h/2$. The level of water in the cylinder is kept constant. Four holes numbered $1, 2, 3$ and $4$ are at the side of the cylinder and at heights $0, h/4, h/2$ and $3h/4$ from the base of the cylinder, respectively. When all four holes are opened together, the hole from which water will reach the farthest distance on the plane $PQ$ is the hole number:

$A$ cylindrical tank having a large diameter is filled with water to a height $H$. $A$ hole of cross-sectional area $5 \,cm^2$ in the tank allows water to drain out. If the water drains out at the rate of $2 \times 10^{-3} \,m^3 \,s^{-1}$, then the value of $H$ is (acceleration due to gravity $= 10 \,ms^{-2}$) (in $\,cm$)

$A$ container of large uniform cross-sectional area $A$ is resting on a horizontal surface and holds two immiscible,non-viscous,and incompressible liquids of densities $d$ and $2d$,each of height $\frac{H}{2}$,as shown. The upper surface of the liquid with lower density is open to the atmosphere. $A$ small hole is made on the wall of the container at height $h$ $(h < \frac{H}{2})$. The initial speed of efflux of the liquid at the hole is:

$A$ cylindrical tank is filled with water to a level of $3 \,m$. $A$ hole is opened at a height of $52.5 \,cm$ from the bottom. The ratio of the area of the hole to that of the cross-sectional area of the tank is $0.1$. The square of the speed with which water will be coming out from the orifice is $(g=10 \,ms^{-2})$.