Consider the input waveforms $A$ and $B$ as shown in the figure. Sketch the output waveform obtained from an $AND$ gate.

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(N/A) For an $AND$ gate,the output $Y$ is $1$ only when both inputs $A$ and $B$ are $1$. Otherwise,the output $Y$ is $0$. Based on the provided input waveforms,we analyze the intervals:
IntervalInputs $(A, B)$Output $(Y = A \cdot B)$
$t \leq t_{1}$$A=0, B=0$$Y=0$
$t_{1}$ to $t_{2}$$A=1, B=0$$Y=0$
$t_{2}$ to $t_{3}$$A=1, B=1$$Y=1$
$t_{3}$ to $t_{4}$$A=0, B=1$$Y=0$
$t_{4}$ to $t_{5}$$A=0, B=0$$Y=0$
$t_{5}$ to $t_{6}$$A=1, B=0$$Y=0$
$t > t_{6}$$A=0, B=0$$Y=0$

Thus,the output waveform remains at a low state $(0)$ for all intervals except between $t_{2}$ and $t_{3}$,where it goes to a high state $(1)$.

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The figure shows two $NAND$ gates followed by a $NOR$ gate. The system is equivalent to the following logic gate:

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For a $NAND$ gate, the inputs and outputs are given in the table below. The values taken by $C, D, E, F$ are respectively:
Input $A$Input $B$Output $Y$
$0$$1$$C$
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$1$$0$$E$
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Identify the logic gate represented by the given circuit.

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The combination of the gates shown in the figure below produces:

To obtain the truth-table shown, from the following logic circuit, the gate $G$ should be
$A$$B$$Y$
$0$$0$$1$
$0$$1$$0$
$1$$0$$1$
$1$$1$$1$

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