Supposing the electron is present in the 4^{t | vedclass

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(D) The number of possible spectral lines emitted when an electron transitions from an excited state $n$ to the ground state is given by the formula $

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(D) The number of possible spectral lines emitted when an electron transitions from an excited state $n$ to the ground state is given by the formula $\frac{n(n-1)}{2}$.For $n = 4$,the number of lines is $\frac{4(4-1)}{2} = 6$.The possible transitions are:$1$. $4 \rightarrow 3$$2$. $4 \rightarrow 2$$3$. $4 \rightarrow 1$$4$. $3 \rightarrow 2$$5$. $3 \rightarrow 1$$6$. $2 \rightarrow 1$Since all the transitions listed in options $A$,$B$,and $C$ are valid individual steps that can occur during the cascade of an electron from $n=4$ to $n=1$,the correct answer is $D$.

Supposing the electron is present in the $4^{th}$ energy level of $H$ atom. When the electron returns to the ground state,the possible transitions would be:

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