Suppose $A$ and $B$ are two points on the line $2x-y+3=0$ and $P(1,2)$ is a point such that $PA=PB$. Then,the mid-point of $AB$ is

  • A
    $\left(\frac{-1}{5}, \frac{13}{5}\right)$
  • B
    $\left(\frac{-7}{5}, \frac{9}{5}\right)$
  • C
    $\left(\frac{7}{5}, \frac{-9}{5}\right)$
  • D
    $\left(\frac{-7}{5}, \frac{-9}{5}\right)$

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