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(C) The complex is $Na[Co(bpy)Cl_4]$.$bpy$ $(2,2'-bipyridine)$ is a bidentate ligand,and $Cl^-$ is a monodentate ligand.Coordination number of $Co = (

Vedclass · Accepted Answer

$9$

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(C) The complex is $Na[Co(bpy)Cl_4]$.$bpy$ $(2,2'-bipyridine)$ is a bidentate ligand,and $Cl^-$ is a monodentate ligand.Coordination number of $Co = (1 	imes 2) + (4 	imes 1) = 6$.Let the oxidation state of $Co$ be $x$.The charge on $Na$ is $+1$,$bpy$ is $0$,and $Cl$ is $-1$.$1 + x + 0 + 4(-1) = 0$$1 + x - 4 = 0$$x - 3 = 0$$x = +3$.Magnitude of oxidation state $= 3$.Sum $= 6 + 3 = 9$.

The sum of the oxidation state (magnitude) and the coordination number of cobalt in $Na[Co(bpy)Cl_4]$ is $.......$ (Given $bpy = 2,2'-bipyridine$)

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