In the given reactions,find the sum of (x + y | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For reaction $(1)$: The starting material is a gem-dibromide $Ph-C(Br)_2-CH_3$. Treatment with $NaNH_2$ (a strong base) causes dehydrohalogenation

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) For reaction $(1)$: The starting material is a gem-dibromide $Ph-C(Br)_2-CH_3$. Treatment with $NaNH_2$ (a strong base) causes dehydrohalogenation to form an alkyne. Two equivalents of $NaNH_2$ are required to remove two molecules of $HBr$ to form the terminal alkyne $Ph-C \equiv CH$ (which is $(A)$). Thus,$x = 2$.For reaction $(2)$: The starting material is $CH_3-CH_2-C(Br)_2-CH_3$. Treatment with $NaNH_2$ causes dehydrohalogenation to form the internal alkyne $CH_3-C \equiv C-CH_3$. Two equivalents of $NaNH_2$ are required to remove two molecules of $HBr$. Thus,$y = 2$.The sum $(x + y) = 2 + 2 = 4$.

In the given reactions,find the sum of $(x + y)$.
$(1)$ $Ph-C(Br)_2-CH_3$ $\xrightarrow{xNaNH_2} (A)$ $\xrightarrow{CH_3I} Ph-C \equiv C-CH_3$
$(2)$ $CH_3-CH_2-C(Br)_2-CH_3 \xrightarrow{yNaNH_2} CH_3-C \equiv C-CH_3$
Find the value of $(x + y)$.

Similar Questions

Which of the following reactions is not correct?

For the alkyne with formula $C_6H_{10}$,the number of alkynes with acidic hydrogens is $x$ and the number of alkynes with no acidic hydrogens is $y$. $x$ and $y$ are respectively:

Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.

$CH_3-C \equiv C-O-CH_3 \xrightarrow{dil. \ H_2SO_4, HgSO_4} \text{major product}$

Alkynes can undergo which of the following reactions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the given reactions,find the sum of $(x + y)$.$(1)$ $Ph-C(Br)_2-CH_3$ $\xrightarrow{xNaNH_2} (A)$ $\xrightarrow{CH_3I} Ph-C \equiv C-CH_3$$(2)$ $CH_3-CH_2-C(Br)_2-CH_3 \xrightarrow{yNaNH_2} CH_3-C \equiv C-CH_3$Find the value of $(x + y)$.