Sulphuric acid reacts with sodium hydroxide a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The balanced chemical equation is: $H_2SO_4 + 2NaOH \longrightarrow Na_2SO_4 + 2H_2O$Initial moles of $H_2SO_4 = 	ext{Molarity} 	imes 	ext{Volu

Vedclass · Accepted Answer

$14.2$

Vedclass · Answer

(C) The balanced chemical equation is: $H_2SO_4 + 2NaOH \longrightarrow Na_2SO_4 + 2H_2O$Initial moles of $H_2SO_4 = 	ext{Molarity} 	imes 	ext{Volume} = 0.2 \ M 	imes 1 \ L = 0.2 \ mol$.Initial moles of $NaOH = 	ext{Molarity} 	imes 	ext{Volume} = 0.2 \ M 	imes 1 \ L = 0.2 \ mol$.According to the stoichiometry,$1 \ mol$ of $H_2SO_4$ requires $2 \ mol$ of $NaOH$.Therefore,$0.2 \ mol$ of $H_2SO_4$ would require $0.4 \ mol$ of $NaOH$.Since only $0.2 \ mol$ of $NaOH$ is available,$NaOH$ is the limiting reagent.From the stoichiometry,$2 \ mol$ of $NaOH$ produces $1 \ mol$ of $Na_2SO_4$.So,$0.2 \ mol$ of $NaOH$ will produce $0.1 \ mol$ of $Na_2SO_4$.Molar mass of $Na_2SO_4 = (2 	imes 23) + 32 + (4 	imes 16) = 142 \ g/mol$.Mass of $Na_2SO_4 = 	ext{moles} 	imes 	ext{molar mass} = 0.1 \ mol 	imes 142 \ g/mol = 14.2 \ g$.

Sulphuric acid reacts with sodium hydroxide as follows:
$H_2SO_4 + 2NaOH \longrightarrow Na_2SO_4 + 2H_2O$
What will be the amount of sodium sulphate formed,when $1 \ L$ of $0.2 \ M$ sulphuric acid is allowed to react with $1 \ L$ of $0.2 \ M$ sodium hydroxide solution (in $g$)?

Similar Questions

According to the reaction $2A + B \to C$,$8 \ mol$ of $A$ and $5 \ mol$ of $B$ will produce how many moles of $C$?

Which of the following is formed when calcium combines with oxygen?

$0.4 \text{ g}$ of dihydrogen is made to react with $7.4 \text{ g}$ of dichlorine to form hydrogen chloride. The volume of hydrogen chloride formed at $273 \text{ K}$ and $1 \text{ bar}$ pressure is: (in $\text{ L}$)

If $0.50 \ mol$ of $CaCl_2$ is mixed with $0.20 \ mol$ of $Na_3PO_4$,the maximum number of moles of $Ca_3(PO_4)_2$ which can be formed,is

The maximum number of moles of $CaSO_4$ produced by the reaction of $0.5 \ mol$ of $H_2SO_4$ with $0.2 \ mol$ of $Ca(OH)_2$ is ........

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Sulphuric acid reacts with sodium hydroxide as follows:$H_2SO_4 + 2NaOH \longrightarrow Na_2SO_4 + 2H_2O$What will be the amount of sodium sulphate formed,when $1 \ L$ of $0.2 \ M$ sulphuric acid is allowed to react with $1 \ L$ of $0.2 \ M$ sodium hydroxide solution (in $g$)?