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Question

(C) The reaction of $SO_2$ with $Cl_2$ in the presence of charcoal (catalyst) gives sulphuryl chloride $(A)$: $SO_2 + Cl_2 \xrightarrow{	ext{charcoal

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'$B$' in solid state exists as an ionic solid

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(C) The reaction of $SO_2$ with $Cl_2$ in the presence of charcoal (catalyst) gives sulphuryl chloride $(A)$: $SO_2 + Cl_2 \xrightarrow{	ext{charcoal}} SO_2Cl_2$ $(A)$.Sulphuryl chloride $(A)$ reacts with white phosphorus $(P_4)$ to give $SO_2$ and phosphorus pentachloride $(B)$: $10SO_2Cl_2 + P_4 ightarrow 4PCl_5$ $(B)$ $+ 10SO_2$.Compound $(B)$ is $PCl_5$.In the solid state,$PCl_5$ exists as an ionic solid $[PCl_4]^+[PCl_6]^-$.Therefore,the correct statement is that '$B$' in the solid state exists as an ionic solid.

Sulphur dioxide on reaction with chlorine in the presence of charcoal gives compound $(A)$. This on reaction with white phosphorus gives $SO_2$ and compound $(B)$. The correct statement about '$B$' is

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