Sudha finds out that the sharp image of the w | vedclass

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(A) When the object is at a large distance (like a building outside),the rays of light coming from it are considered parallel to the principal axis.Ac

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Towards the lens; $15\, cm$

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(A) When the object is at a large distance (like a building outside),the rays of light coming from it are considered parallel to the principal axis.According to the lens formula,for an object at infinity,the image is formed at the principal focus $(F)$.Since the image of the nearby window pane was formed at $15\, cm$,the building (which is much further away) will form an image closer to the focal point of the lens.Therefore,Sudha should move the screen towards the lens to obtain a sharp image of the building.The approximate focal length of the lens is equal to the image distance of the distant object,which is $15\, cm$.

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