Study the speed$-$time graph of a car below and answer the following questions
$(a)$ What type of motion is represented by $OA$ ?
$(b)$ Find acceleration from $B$ to $C$.
$(c)$ Calculate the distance covered by the body from $A$ to $B$.
$(a)$ Uniformly accelerated motion.
$(b)$ Acceleration is given by the slope of speedtime graph, i.e., $a=(0-60) /(80-60)$ $=-3 m s ^{-2}$
$(c)$ Distance covered is equal'to the area under the speed-time graph, therefore,
$S=60 \times(60-20)=2400 m$
A car manufacturer advertises that the brakes are so perfect that the car stops instantaneously. Comment.
Name a physical quantity that essentially changes as a body moves.
A body moves with a velocity of $2\, m s ^{-1}$ for $5\, s$, then its velocity increases uniformly to $10\, m s ^{-1}$ in next $5\, s.$ Thereafter, its velocity begins to decrease at a uniform rate until it comes to rest after $5\, s$.
$(i)$ Plot a velocity-time graph for the motion of the body.
$(ii)$ From the graph, find the total distance covered by the body after $2\, s$ and $12\, s$.
Two cars moving in opposite directions cover same distance $'d'$ in one hour. If the cars were moving in north$-$south direction, what will be their displacement in one hour ?
The velocity$-$time graph of a car is given below. The car weighs $1000\, kg$.
$(i)$ What is the distance travelled by the car in the first $2$ seconds ?
$(ii)$ What is the braking force at the end of $5$ seconds to bring the car to a stop within one second ?