(D) In a $ccp$ lattice,the number of oxide ions $(O^{2-})$ per unit cell is $4$.Number of tetrahedral voids $= 2 \times 4 = 8$.Number of octahedral vo

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(D) In a $ccp$ lattice,the number of oxide ions $(O^{2-})$ per unit cell is $4$.Number of tetrahedral voids $= 2 \times 4 = 8$.Number of octahedral voids $= 4$.Number of $A$ ions (occupying $1/4$ of tetrahedral voids) $= \frac{1}{4} \times 8 = 2$.Number of $B$ ions (occupying all octahedral voids) $= 4$.Ratio of $A : B : O = 2 : 4 : 4$,which simplifies to $1 : 2 : 2$.Therefore,the formula of the oxide is $AB_2O_2$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

The structure of a mixed oxide is cubic close packed $(ccp)$. The cubic unit cell of the mixed oxide is composed of oxide ions. One-fourth of the tetrahedral voids are occupied by divalent metal $A$ and the octahedral voids are occupied by a monovalent metal $B$. The formula of the oxide is

A
$ABO_2$
B
$A_2BO_2$
C
$A_2B_3O_4$
D
$AB_2O_2$

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The structure of a mixed oxide is cubic close packed $(ccp)$. The cubic unit cell of the mixed oxide is composed of oxide ions. One-fourth of the tetrahedral voids are occupied by divalent metal $A$ and the octahedral voids are occupied by a monovalent metal $B$. The formula of the oxide is

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$A$ point object on the principal axis at a distance $15\, cm$ in front of a concave mirror of radius of curvature $20\, cm$ has a velocity of $2\, mm/s$ perpendicular to the principal axis. The velocity of the image at that instant will be.......$mm/s$.

If the roots of the equation $x^2+px+q=0$ are $\alpha$ and $\beta$,and the roots of the equation $x^2-rx+s=0$ are $\alpha^4$ and $\beta^4$,then the roots of the equation $x^2-4qx+2q^2-r=0$ will be

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