Steam at 100^{circ} C is passed into 1 kg of | vedclass

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(B) According to the principle of calorimetry,Heat lost by steam = Heat gained by water and calorimeter.Let $m$ be the mass of steam condensed in gram

Vedclass · Accepted Answer

$0.18$

Vedclass · Answer

(B) According to the principle of calorimetry,Heat lost by steam = Heat gained by water and calorimeter.Let $m$ be the mass of steam condensed in grams.Heat lost by steam = $m 	imes L + m 	imes C_w 	imes (T_{steam} - T_{final})$$= m 	imes 540 + m 	imes 1 	imes (100 - 90) = 550m \ cal$.Heat gained by water and calorimeter = $(m_{water} + m_{eq}) 	imes C_w 	imes (T_{final} - T_{initial})$$= (1000 \ g + 200 \ g) 	imes 1 	imes (90 - 9) = 1200 	imes 81 = 97200 \ cal$.Equating the two: $550m = 97200$.$m = \frac{97200}{550} \approx 176.7 \ g$.Converting to $kg$,$m \approx 0.1767 \ kg$,which is approximately $0.18 \ kg$.

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