Statement (A): Among the oxides of nitrogen,N | vedclass

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(D) Statement $(A)$: $NO$ has $11$ valence electrons (odd number),making it paramagnetic. $NO_2$ has $17$ valence electrons (odd number),making it par

Vedclass · Accepted Answer

Both $(A)$ and $(B)$ are correct

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(D) Statement $(A)$: $NO$ has $11$ valence electrons (odd number),making it paramagnetic. $NO_2$ has $17$ valence electrons (odd number),making it paramagnetic. Thus,statement $(A)$ is correct.Statement $(B)$: In the gaseous state,$NO$ exists as a monomer with an unpaired electron,making it paramagnetic. In the liquid and solid states,$NO$ dimerizes to form $N_2O_2$,where all electrons are paired,making it diamagnetic. Thus,statement $(B)$ is correct.Therefore,both statements are correct,and option $(D)$ is the correct answer.

Statement $(A)$: Among the oxides of nitrogen,$NO$ and $NO_2$ are paramagnetic.
Statement $(B)$: $NO$ is paramagnetic in the gaseous state and diamagnetic in the liquid state.
The correct answer is:

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Statement $(A)$: Among the oxides of nitrogen,$NO$ and $NO_2$ are paramagnetic.Statement $(B)$: $NO$ is paramagnetic in the gaseous state and diamagnetic in the liquid state.The correct answer is: