Starting from rest a scooter acquires a velocity of $36\, km h^{-1}$ in $10 \,s$ and then brakes are applied it takes $20\, s$ to stop. Calculate acceleration and distance travelled.
Starting from rest a scooter acquires a velocity of $36\, km h^{-1}$ in $10 \,s$ and then brakes are applied it takes $20\, s$ to stop. Calculate acceleration and distance travelled.
$u=36 km h ^{-1}=10 m s ^{-1}$
$u=0$
$t=10 s$
$\therefore \quad a=\frac{v-u}{t}$.
$=\frac{10}{10}=1 ms ^{-2}$
$S=u t+\frac{1}{2} a t^{2}$
$=0+\frac{1}{2} \times 1 \times 400$
$=200 \,m$,
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