Starting from a point P, Sachin walked 20 ,m | vedclass

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Question

(A) Let the starting point be $P.$ $1$. Sachin walks $20 \,m$ South to reach point $A.$ $2$. He turns left (East) and walks $30 \,m$ to reach point $B

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$10 \,m$ West

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(A) Let the starting point be $P.$ $1$. Sachin walks $20 \,m$ South to reach point $A.$ $2$. He turns left (East) and walks $30 \,m$ to reach point $B.$ $3$. He turns left (North) and walks $20 \,m$ to reach point $C.$ $4$. He turns left (West) and walks $40 \,m$ to reach point $Q.$ Since he walked $30 \,m$ East and then $40 \,m$ West,his net displacement in the East-West direction is $40 \,m - 30 \,m = 10 \,m$ towards the West. Since he walked $20 \,m$ South and then $20 \,m$ North,his net displacement in the North-South direction is $0.$ Therefore,point $Q$ is $10 \,m$ to the West of point $P.$

Starting from a point $P,$ Sachin walked $20 \,m$ towards South. He turned left and walked $30 \,m.$ He then turned left and walked $20 \,m.$ He again turned left and walked $40 \,m$ and reached a point $Q.$ How far and in which direction is the point $Q$ from the point $P$?

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