Specific conductance of $0.1 \ M \ HNO_3$ is $6.3 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$. The molar conductance of the solution is
- A$315 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
- B$6300 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
- C$63.0 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
- D$630 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
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Similar Questions
Molar conductivity of $0.02 \ M$ weak acid is $7.92 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and its molar conductivity at infinite dilution is $232.7 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. Calculate the degree of dissociation of the weak acid.
Conductivity of a solution is directly proportional to
Easy
View SolutionMatch List-$I$ with List-$II$:
List-$I$ (Parameter) List-$II$ (Unit) $a$. Cell constant $i$. $S\, cm^{2}\, mol^{-1}$ $b$. Molar conductivity $ii$. Dimensionless $c$. Conductivity $iii$. $m^{-1}$ $d$. Degree of dissociation of electrolyte $iv$. $\Omega^{-1}\, m^{-1}$
Choose the most appropriate answer from the options given below:
| List-$I$ (Parameter) | List-$II$ (Unit) |
| $a$. Cell constant | $i$. $S\, cm^{2}\, mol^{-1}$ |
| $b$. Molar conductivity | $ii$. Dimensionless |
| $c$. Conductivity | $iii$. $m^{-1}$ |
| $d$. Degree of dissociation of electrolyte | $iv$. $\Omega^{-1}\, m^{-1}$ |
Choose the most appropriate answer from the options given below:
The correct order of equivalent conductance of $LiCl$, $NaCl$ and $KCl$ at infinite dilution is
Medium
View SolutionThe conductivity of a centimolar solution of $KCl$ at $25^{\circ} C$ is $0.0210 \, \Omega^{-1} cm^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} C$ is $60 \, \Omega$. The value of the cell constant is $......... \, cm^{-1}$.
DifficultNEET 2023
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