(N/A) The competition between substitution and elimination reactions in alkyl halides depends on several structural and reaction conditions:
$1$. Nature of Alkyl Halide: Primary $(1^{\circ})$ alkyl halides prefer substitution $(S_N2)$ due to less steric hindrance. Tertiary $(3^{\circ})$ alkyl halides prefer elimination $(E2)$ due to high steric hindrance around the electrophilic carbon,which hinders nucleophilic attack but facilitates the removal of a $\beta$-hydrogen by a base.
$2$. Nature of Base: Strong and bulky bases favor elimination,while weaker or less hindered bases favor substitution.
$3$. Solvent and Temperature: High temperatures generally favor elimination (as it is entropy-favored),while lower temperatures favor substitution.
Examples:
- Substitution: $CH_3CH_2Cl + KOH(aq) \rightarrow CH_3CH_2OH + KCl$.
- Elimination: $CH_3CH_2Cl + KOH(alc) \rightarrow CH_2=CH_2 + KCl + H_2O$.