Solve: i x^2 - 3 x - 2 i = 0 | vedclass

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(C) Given equation: $i x^2 - 3 x - 2 i = 0$Since $i^2 = -1$,we can write $-3x$ as $i^2 x - 4x$ or manipulate the middle term.Alternatively,using the q

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$-i$ and $-2 i$

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(C) Given equation: $i x^2 - 3 x - 2 i = 0$Since $i^2 = -1$,we can write $-3x$ as $i^2 x - 4x$ or manipulate the middle term.Alternatively,using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$:Here $a = i$,$b = -3$,$c = -2i$.$x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(i)(-2i)}}{2(i)}$$x = \frac{3 \pm \sqrt{9 + 8i^2}}{2i}$$x = \frac{3 \pm \sqrt{9 - 8}}{2i}$$x = \frac{3 \pm \sqrt{1}}{2i}$$x = \frac{3 \pm 1}{2i}$Case $1$: $x = \frac{3+1}{2i} = \frac{4}{2i} = \frac{2}{i} = -2i$Case $2$: $x = \frac{3-1}{2i} = \frac{2}{2i} = \frac{1}{i} = -i$Thus,the solutions are $x = -i$ and $x = -2i$.

Solve: $i x^2 - 3 x - 2 i = 0$

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