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(D) For equation $I$: $2x^2 + 3x - 20 = 0$$2x^2 + 8x - 5x - 20 = 0$$2x(x + 4) - 5(x + 4) = 0$$(2x - 5)(x + 4) = 0$So,$x = 2.5$ or $x = -4$.For equatio

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If $x \geq y$

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(D) For equation $I$: $2x^2 + 3x - 20 = 0$$2x^2 + 8x - 5x - 20 = 0$$2x(x + 4) - 5(x + 4) = 0$$(2x - 5)(x + 4) = 0$So,$x = 2.5$ or $x = -4$.For equation $II$: $2y^2 + 19y + 44 = 0$$2y^2 + 8y + 11y + 44 = 0$$2y(y + 4) + 11(y + 4) = 0$$(2y + 11)(y + 4) = 0$So,$y = -5.5$ or $y = -4$.Comparing the values:If $x = 2.5$,then $x > y$ (since $2.5 > -4$ and $2.5 > -5.5$).If $x = -4$,then $x = y$ (when $y = -4$) and $x > y$ (when $y = -5.5$).Combining these,we get $x \geq y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $2x^2 + 3x - 20 = 0$
$II.$ $2y^2 + 19y + 44 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $2x^2 + 3x - 20 = 0$$II.$ $2y^2 + 19y + 44 = 0$