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(B) For equation $I: 3x^2 + 15x + 18 = 0$Divide by $3$: $x^2 + 5x + 6 = 0$$(x + 3)(x + 2) = 0$So,$x_1 = -3$ and $x_2 = -2$.For equation $II: 2y^2 + 15

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if $x \ge y$

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(B) For equation $I: 3x^2 + 15x + 18 = 0$Divide by $3$: $x^2 + 5x + 6 = 0$$(x + 3)(x + 2) = 0$So,$x_1 = -3$ and $x_2 = -2$.For equation $II: 2y^2 + 15y + 27 = 0$$2y^2 + 6y + 9y + 27 = 0$$2y(y + 3) + 9(y + 3) = 0$$(2y + 9)(y + 3) = 0$So,$y_1 = -4.5$ and $y_2 = -3$.Comparing the roots:$x = \{-3, -2\}$$y = \{-4.5, -3\}$Since $-3 \ge -4.5$,$-3 \ge -3$,$-2 \ge -4.5$,and $-2 \ge -3$,we conclude that $x \ge y$.

Solve the given two equations and select the correct answer from the given options.
$I. \quad 3x^2 + 15x + 18 = 0$
$II. \quad 2y^2 + 15y + 27 = 0$

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Solve the given two equations and select the correct answer from the given options.$I. \quad 3x^2 + 15x + 18 = 0$$II. \quad 2y^2 + 15y + 27 = 0$