Solve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt[3]{4913}$
$II.$ $13y + 3x = 246$

  • A
    if $x > y$
  • B
    if $x < y$
  • C
    if $x \ge y$
  • D
    if $x \le y$

Explore More

Similar Questions

Solve the given two equations and select the correct option.
$I.$ $x = \frac{\sqrt{256}}{\sqrt{576}}$
$II.$ $3y^2 + y - 2 = 0$

The coefficient of $x$ in the equation $x^2 + px + q = 0$ was taken as $17$ in place of $13$. Its roots were found to be $-2$ and $-15$. The roots of the original equation are:

Let $\alpha$ and $\beta$ be the roots of the equation $5x^{2} + 6x - 2 = 0$. If $S_{n} = \alpha^{n} + \beta^{n}$ for $n = 1, 2, 3, \ldots$,then:

In a triangle $ABC$,the value of $\angle A$ is given by $5\cos A + 3 = 0$. Then,the equation whose roots are $\sin A$ and $\tan A$ is:

Difficult
View Solution

Find the complete set of values of $k$ for which the equation $4^x - (k + 2)2^x + 2k = 0$ has exactly one positive root.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo