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(D) Step $1$: Solve for $x$ from equation $I$.$x^{2} = 64 \Rightarrow x = \pm 8$.So,$x = 8$ or $x = -8$.Step $2$: Solve for $y$ from equation $II$.$2y

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if $x = y$ or the relationship between $x$ and $y$ cannot be established.

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(D) Step $1$: Solve for $x$ from equation $I$.$x^{2} = 64 \Rightarrow x = \pm 8$.So,$x = 8$ or $x = -8$.Step $2$: Solve for $y$ from equation $II$.$2y^{2} + 25y + 72 = 0$.We need to factorize the quadratic equation: $2y^{2} + 16y + 9y + 72 = 0$.$2y(y + 8) + 9(y + 8) = 0$.$(2y + 9)(y + 8) = 0$.So,$y = -8$ or $y = -4.5$.Step $3$: Compare $x$ and $y$ values.If $x = 8$,then $x > y$ (since $8 > -8$ and $8 > -4.5$).If $x = -8$,then $x = y$ (when $y = -8$) and $x Since the relationship varies depending on the values chosen,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2} = 64$
$II.$ $2y^{2} + 25y + 72 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2} = 64$$II.$ $2y^{2} + 25y + 72 = 0$