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(A) Step $1$: Solve for $x$.$x = (1331)^{1/3} = (11^3)^{1/3} = 11$.Step $2$: Solve the quadratic equation $2y^2 - 17y + 36 = 0$.Using the splitting th

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if $x > y$

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(A) Step $1$: Solve for $x$.$x = (1331)^{1/3} = (11^3)^{1/3} = 11$.Step $2$: Solve the quadratic equation $2y^2 - 17y + 36 = 0$.Using the splitting the middle term method:$2y^2 - 9y - 8y + 36 = 0$$y(2y - 9) - 4(2y - 9) = 0$$(y - 4)(2y - 9) = 0$So,$y = 4$ or $y = 9/2 = 4.5$.Step $3$: Compare $x$ and $y$.Since $x = 11$ and the values of $y$ are $4$ and $4.5$,it is clear that $11 > 4$ and $11 > 4.5$.Therefore,$x > y$.

Solve the given two equations and select the correct option.
$I.$ $x = (1331)^{1/3}$
$II.$ $2y^2 - 17y + 36 = 0$

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Solve the given two equations and select the correct option.$I.$ $x = (1331)^{1/3}$$II.$ $2y^2 - 17y + 36 = 0$