Solve the given inequality for real x: frac{x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $

Vedclass · Accepted Answer

$(-\infty, -6)$

Vedclass · Answer

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $(6)$:$\frac{2x - 3x}{6} > 1$Simplify the numerator:$-\frac{x}{6} > 1$Multiply both sides by $6$:$-x > 6$Multiply by $-1$ and reverse the inequality sign:$x Thus,the solution set is $(-\infty, -6)$.

Solve the given inequality for real $x$: $\frac{x}{3} > \frac{x}{2} + 1$

Similar Questions

Solve $24x < 100$,when $x$ is an integer.

The solution set of $\frac{x^{2}}{x^{2}+1} < 0$ is

If $|x-2| \geq 8$,then $x \in$

Solve the given inequality and show the graph of the solution on a number line:
$5x - 3 \geq 3x - 5$

Solve the given inequality for real $x$: $4x + 3 < 5x + 7$

Vedclass Test Series

Exam Paper Generator

Online Exam Module