Solve the following system of inequalities gr | vedclass

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(A) To solve the system of inequalities $3x + y > 0$ and $3x + y < 3$ graphically,we first consider the boundary lines: $1$. For $3x + y = 0$,we plot

Vedclass · Accepted Answer

The region between the lines $3x + y = 0$ and $3x + y = 3$.

Vedclass · Answer

(A) To solve the system of inequalities $3x + y > 0$ and $3x + y $1$. For $3x + y = 0$,we plot the line passing through $(0, 0)$ and $(1, -3)$. Since the inequality is $3x + y > 0$,the solution region is the half-plane above this line. $2$. For $3x + y = 3$,we plot the line passing through $(1, 0)$ and $(0, 3)$. Since the inequality is $3x + y $3$. The intersection of these two regions is the strip between the two parallel lines $3x + y = 0$ and $3x + y = 3$.

Solve the following system of inequalities graphically: $3x + y > 0$ and $3x + y < 3$.

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