Solve the following pair of linear equations | vedclass

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Question

(C) Given equations are:$(1) x + 11y = 1$$(2) 8x + 13y = 2$From equation $(1)$,we get $x = 1 - 11y$.Substitute this value of $x$ into equation $(2)$:$

Vedclass · Accepted Answer

$(\frac{3}{25}, \frac{2}{25})$

Vedclass · Answer

(C) Given equations are:$(1) x + 11y = 1$$(2) 8x + 13y = 2$From equation $(1)$,we get $x = 1 - 11y$.Substitute this value of $x$ into equation $(2)$:$8(1 - 11y) + 13y = 2$$8 - 88y + 13y = 2$$8 - 75y = 2$$-75y = 2 - 8$$-75y = -6$$y = \frac{-6}{-75} = \frac{2}{25}$.Now,substitute $y = \frac{2}{25}$ into the expression for $x$:$x = 1 - 11(\frac{2}{25})$$x = 1 - \frac{22}{25} = \frac{25 - 22}{25} = \frac{3}{25}$.Thus,the solution is $(x, y) = (\frac{3}{25}, \frac{2}{25})$.

Solve the following pair of linear equations by the method of substitution: $x + 11y = 1$ and $8x + 13y = 2$.

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