Solve the following pair of linear equations by the elimination method and the substitution method:
$3x + 4y = 10$ and $2x - 2y = 2$

(N/A) By elimination method:
$3x + 4y = 10$ $...(1)$
$2x - 2y = 2$ $...(2)$
Multiplying equation $(2)$ by $2$,we obtain:
$4x - 4y = 4$ $...(3)$
Adding equation $(1)$ and $(3)$,we obtain:
$7x = 14$
$x = 2$ $...(4)$
Substituting $x = 2$ in equation $(1)$,we obtain:
$3(2) + 4y = 10$
$6 + 4y = 10$
$4y = 4$
$y = 1$
Hence,$x = 2, y = 1$.
By substitution method:
From equation $(2)$,we obtain:
$2x = 2 + 2y$
$x = 1 + y$ $...(5)$
Putting this value in equation $(1)$,we obtain:
$3(1 + y) + 4y = 10$
$3 + 3y + 4y = 10$
$7y = 7$
$y = 1$
Substituting the value $y = 1$ in equation $(5)$,we obtain:
$x = 1 + 1 = 2$
Therefore,$x = 2, y = 1$.