Solve the following inequality graphically in a two-dimensional plane: $5x + 2y \leq 10$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Step $1$: Consider the corresponding equation $5x + 2y = 10$.
Step $2$: Find the intercepts of the line. If $x = 0$,then $2y = 10$,so $y = 5$. The point is $(0, 5)$. If $y = 0$,then $5x = 10$,so $x = 2$. The point is $(2, 0)$.
Step $3$: Draw the line passing through $(0, 5)$ and $(2, 0)$. Since the inequality is $\leq$,the line is solid.
Step $4$: Test the origin $(0, 0)$. Substituting into the inequality: $5(0) + 2(0) \leq 10$,which is $0 \leq 10$. This is true.
Step $5$: Since the statement is true,the solution region is the half-plane containing the origin.

Explore More

Similar Questions

Solve the given inequality graphically in a two-dimensional plane: $x > -3$

Solve the following inequality graphically in a two-dimensional plane: $y + 8 > 2x$.

Consider the following statements :
Statement $(I)$ : The set of all solutions of the linear inequalities $3x + 8 < 17$ and $2x + 8 \geq 12$ are $x < 3$ and $x \geq 2$ respectively.
Statement $(II)$ : The common set of solutions of linear inequalities $3x + 8 < 17$ and $2x + 8 \geq 12$ is $(2, 3)$.
Which of the following is true?

Solve $(8-t)^2 < (t^2-3t-10)$

Solve the inequalities and represent the solution graphically on a number line:
$5(2x - 7) - 3(2x + 3) \leq 0$,$2x + 19 \leq 6x + 47$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo