Solve the following inequality: $\frac{|x+2|-x}{x} < 2$

Let $a$ and $b$ be two positive real numbers such that $a+2b \leq 1$. Let $A_1$ and $A_2$ be respectively the areas of circles with radii $ab^3$ and $b^2$. Then,the maximum possible value of $\frac{A_1}{A_2}$ is

$A$ solution is to be kept between $40^{\circ} C$ and $45^{\circ} C$. What is the range of temperature in degree Fahrenheit,if the conversion formula is $F = \frac{9}{5} C + 32$?

The solution set of the inequation $\frac{x^{2}+6x-7}{|x+4|} < 0$ is

The region formed by the inequalities $2x + 3y - 5 \leq 0$,$4x - 3y + 2 \leq 0$,and $x \geq 0$ is:

Solve the following inequality: $\frac{|x-1|}{x+2} < 1$.