(A) The given inequality is $3x + 8 > 2$. Subtract $8$ from both sides: $3x + 8 - 8 > 2 - 8$ $3x > -6$ Divide both sides by $3$: $\frac{3x}{3} > \frac

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(A) The given inequality is $3x + 8 > 2$. Subtract $8$ from both sides: $3x + 8 - 8 > 2 - 8$ $3x > -6$ Divide both sides by $3$: $\frac{3x}{3} > \frac{-6}{3}$ $x > -2$ When $x$ is a real number,the solution set consists of all real numbers greater than $-2$. Thus,the solution set is $(-2, \infty)$.