Solve $\frac{3x-4}{2} \geq \frac{x+1}{4}-1$. Show the graph of the solutions on a number line.

(N/A) We have $\frac{3x-4}{2} \geq \frac{x+1}{4}-1$.
Multiplying both sides by $4$ to clear the denominators:
$2(3x-4) \geq (x+1) - 4$
$6x - 8 \geq x - 3$
Subtract $x$ from both sides:
$5x - 8 \geq -3$
Add $8$ to both sides:
$5x \geq 5$
Divide by $5$:
$x \geq 1$.
The solution set is $[1, \infty)$. The graphical representation is a solid circle at $1$ with a ray extending to the right.