Solutions of two electrolytes $A$ and $B$ are diluted. The $\Lambda_m$ of $B$ increases $1.5$ times while that of $A$ increases $25$ times. Which of the two is a strong electrolyte? Justify your answer.

If the equivalent conductance of $1 \ M$ benzoic acid is $12.8 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ and the equivalent conductances of benzoate ion and $H^{+}$ ion are $42$ and $288.42 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively,its degree of dissociation is ............. $\%$

Limiting molar conductivity of $NH_4OH$ [i.e.,$\Lambda ^o_{m(NH_4OH)}$] is equal to:

The conductance of a $0.0015 \ M$ aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized $Pt$ electrodes. The distance between the electrodes is $120 \ cm$ with an area of cross section of $1 \ cm^2$. The conductance of this solution was found to be $5 \times 10^{-7} \ S$. The $pH$ of the solution is $4$. The value of limiting molar conductivity $\left(\Lambda_{m}^0\right)$ of this weak monobasic acid in aqueous solution is $Z \times 10^2 \ S \ cm^{2} \ mol^{-1}$. The value of $Z$ is

Suggest a way to determine the $\Lambda _m^o$ value of water.

The conductivity of a solution of concentration $0.1 \ mol \ L^{-1}$ of a weak monobasic acid $(HA)$ (in $S \ cm^{-1}$) is (Given $\Lambda_{HA}^{\circ}=400 \ S \ cm^2 \ mol^{-1}$ and degree of dissociation $(\alpha)$ of $HA=0.02$)