The solution of sodium metal in liquid ammonia is a strong reducing agent due to the presence of:

  • A
    solvated sodium ions
  • B
    solvated hydrogen ions
  • C
    sodium atoms or sodium hydroxide
  • D
    solvated electrons

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The nitrate of which metal leaves a metallic globule upon strong heating?

What is the product of the reaction between aluminium and aqueous $NaOH$?

The correct statements are:
$I$. The low solubility of $LiF$ is due to its high lattice enthalpy.
$II$. $LiBr$ is soluble in acetone.
$III$. $LiCl$ is soluble in pyridine.
$IV$. The order of melting points of alkali metal halides is $MF > MCl > MBr > MI$.

Starting with sodium chloride,how would you proceed to prepare:
$(i)$ sodium metal
$(ii)$ sodium hydroxide
$(iii)$ sodium peroxide
$(iv)$ sodium carbonate?

Due to low ionization energy,alkali metals are...

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