Sodium thiosulphate is prepared by:
- AReducing $Na_2SO_4$ solution with $H_2S$
- BBoiling $Na_2SO_3$ solution with $S$ in alkaline medium
- CNeutralising $H_2S_2O_3$ solution with $NaOH$
- DBoiling $Na_2SO_3$ solution with $S$ in acidic medium
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View SolutionAssertion : Both rhombic and monoclinic sulphur exist as $S_8$ but oxygen exists as $O_2$.
Reason : Oxygen forms $p\pi-p\pi$ multiple bond due to small size and small bond length but $p\pi-p\pi$ bonding is not possible in sulphur.
Reason : Oxygen forms $p\pi-p\pi$ multiple bond due to small size and small bond length but $p\pi-p\pi$ bonding is not possible in sulphur.
DifficultAIIMS 2017
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