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(C) The reaction of sodium nitrite with sulphuric acid is: $2NaNO_2 + H_2SO_4 \rightarrow Na_2SO_4 + 2HNO_2$. The $HNO_2$ formed is unstable and decom

Vedclass · Accepted Answer

$NO, NO$

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(C) The reaction of sodium nitrite with sulphuric acid is: $2NaNO_2 + H_2SO_4 \rightarrow Na_2SO_4 + 2HNO_2$. The $HNO_2$ formed is unstable and decomposes: $3HNO_2 \rightarrow HNO_3 + 2NO + H_2O$. Thus,$X$ is $NO$.Gold dissolves in aqua regia $(HNO_3 + 3HCl)$ to form chloroauric acid and nitric oxide: $Au + HNO_3 + 4HCl \rightarrow H[AuCl_4] + NO + 2H_2O$. Thus,$Y$ is $NO$.Therefore,both $X$ and $Y$ are $NO$.

Sodium nitrite is reacted with $H_2SO_4$ to form $NaHSO_4$,$HNO_3$,water and $X$. Gold is dissolved in aqua regia to form water,$AuCl_4^{-}$ and $Y$. $X$ and $Y$ are respectively

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