Sodium generally does not show an oxidation s | vedclass

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Question

(B) The electronic configuration of $Na$ is $[Ne] 3s^1$. After the removal of one electron,it achieves the stable noble gas configuration of $Ne$ $(1s

Vedclass · Accepted Answer

High second ionization potential

Vedclass · Answer

(B) The electronic configuration of $Na$ is $[Ne] 3s^1$. After the removal of one electron,it achieves the stable noble gas configuration of $Ne$ $(1s^2 2s^2 2p^6)$. Removing a second electron requires a very high amount of energy because it involves breaking the stable octet configuration of the $Ne$ core. Therefore,the second ionization potential of $Na$ is extremely high,making the $+2$ oxidation state energetically unfavorable. Thus,$B$ is the correct option.

Element	$IE_1$	$IE_2$	$IE_3$
$P$	$495.8$	$4562$	$6910$
$Q$	$737.7$	$1451$	$7733$
$R$	$577.5$	$1817$	$2745$

Sodium generally does not show an oxidation state of $+2$,because of its

Similar Questions

The first three ionisation energies (in $kJ/mol$) of three representative elements are given below:

Element $IE_1$ $IE_2$ $IE_3$

$P$ $495.8$ $4562$ $6910$

$Q$ $737.7$ $1451$ $7733$

$R$ $577.5$ $1817$ $2745$

Which of the following options is incorrect?

Correct order of $3^{rd}$ Ionisation energy of $B, C, N$ and $O$ will be

Which ionisation potential $(IP)$ in the following equations involves the greatest amount of energy?

The correct order of first ionization enthalpy for the given four elements is:

Based on the values of $IE_1$ and $IE_2$,which of the following represents an alkali metal?

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