Six-elevenths of a number is equal to 22 % of | vedclass

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(D) Let the first number be $x$,the second number be $y$,and the third number be $z$.Given,$z = 2400$.According to the problem,$y = \frac{1}{4} 	imes

Vedclass · Accepted Answer

$108.9$

Vedclass · Answer

(D) Let the first number be $x$,the second number be $y$,and the third number be $z$.Given,$z = 2400$.According to the problem,$y = \frac{1}{4} 	imes z = \frac{1}{4} 	imes 2400 = 600$.Also,$\frac{6}{11} 	imes x = 22 \% 	ext{ of } y$.$\frac{6}{11} 	imes x = \frac{22}{100} 	imes 600$.$\frac{6}{11} 	imes x = 22 	imes 6 = 132$.$x = \frac{132 	imes 11}{6} = 22 	imes 11 = 242$.We need to find $45 \%$ of the first number $(x)$:$45 \% 	ext{ of } 242 = \frac{45}{100} 	imes 242 = 0.45 	imes 242 = 108.9$.

Six-elevenths of a number is equal to $22 \%$ of the second number. The second number is equal to one-fourth of the third number. The value of the third number is $2400$. What is $45 \%$ of the first number?

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