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The unit's digit of the number $6^{256} - 4^{256}$ is

If $p=9$ and $q=\sqrt{17}$,then the value of $(p^{2}-q^{2})^{\frac{-1}{3}}$ is equal to

$48 \div 12 \times \left( \frac{9}{8} \text{ of } \frac{4}{3} + \frac{3}{4} \text{ of } \frac{2}{3} \right) = ?$

The value of: $\sqrt{\frac{0.324 \times 0.081 \times 4.624}{1.5625 \times 0.0289 \times 72.9 \times 64}}$

$12.1212 + 17.0005 - 9.1102 = ?$

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