Simplify: 5 sqrt{2} + 2 sqrt{8} - 3 sqrt{32} | vedclass

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(B) To simplify the expression $5 \sqrt{2} + 2 \sqrt{8} - 3 \sqrt{32} + 4 \sqrt{128}$, we first simplify each radical term:$1$. $5 \sqrt{2} = 5 \sqrt{

Vedclass · Accepted Answer

$29$

Vedclass · Answer

(B) To simplify the expression $5 \sqrt{2} + 2 \sqrt{8} - 3 \sqrt{32} + 4 \sqrt{128}$, we first simplify each radical term:$1$. $5 \sqrt{2} = 5 \sqrt{2}$$2$. $2 \sqrt{8} = 2 \sqrt{4 	imes 2} = 2 	imes 2 \sqrt{2} = 4 \sqrt{2}$$3$. $3 \sqrt{32} = 3 \sqrt{16 	imes 2} = 3 	imes 4 \sqrt{2} = 12 \sqrt{2}$$4$. $4 \sqrt{128} = 4 \sqrt{64 	imes 2} = 4 	imes 8 \sqrt{2} = 32 \sqrt{2}$Now, substitute these values back into the expression:$5 \sqrt{2} + 4 \sqrt{2} - 12 \sqrt{2} + 32 \sqrt{2}$Combine the coefficients:$(5 + 4 - 12 + 32) \sqrt{2} = 29 \sqrt{2}$

Simplify: $5 \sqrt{2} + 2 \sqrt{8} - 3 \sqrt{32} + 4 \sqrt{128}$ (in $\sqrt{2}$)

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