Shown below are the black body radiation curv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute tempe

Vedclass · Accepted Answer

Vedclass · Answer

(A) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute temperature $T$,i.e.,$\lambda_m \propto \frac{1}{T}$.Given $T_2 > T_1$,it follows that $\lambda_{m_2} This means the peak of the intensity-wavelength curve for the higher temperature $T_2$ shifts towards a shorter wavelength (left side) compared to the curve for $T_1$.Additionally,according to the Stefan-Boltzmann law,the total energy emitted per unit area per unit time is proportional to $T^4$,so the intensity $I$ for $T_2$ will be higher than for $T_1$ at all wavelengths.Therefore,the correct plot is the one where the curve for $T_2$ is higher and its peak is shifted to the left relative to the curve for $T_1$.

Shown below are the black body radiation curves at temperatures $T_1$ and $T_2$ $(T_2 > T_1)$. Which of the following plots is correct?

Similar Questions

If a vessel with black spots is heated to a very high temperature and then taken into a dark room,then:

If Earth did not have an atmosphere,the temperature would be . . . . . . .

For a perfectly black body,its absorptive power is

$A$ body,which emits radiations of all possible wavelengths,is known as

Which of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module